A Better Place Than The Six And Eight
When I talk to place bet players, most of them seem confident that the best place bet is the 6 or 8. This bet pays 7:6, that is when you bet $30, you’ll win $35. Some people place bet both numbers together, increasing their chances of winning, but at the same time, exposing their money to more risk.
If the seven rolls, you’re out $60 (2 x $30), which means you have to win twice more just to get ahead. The seven should roll six times in 36 rolls, and the combination of the 6 and 8 should roll ten times (five times each). So, in 36 rolls, you should win 10 times (at $35) and lose six times (at $60). This turns out to be a net loss of $10 ($350-$360).
Are there any other numbers that we can bet on which could provide a more profitable win than the six and eight? Let’s take a look at the four and ten, with its standard 9:5 odds.
In 36 rolls, the four and ten combination should roll six times (three each), the same amount as the seven. By betting $25 on both the four and ten, you should win six times (6 x $45) and lose six times (6 x $50), resulting in a net loss of $30 ($270-$300). However, there are some special circumstances surrounding these numbers. The four and ten can be “bought” for a 5% commission. Plus, some casinos only charge this “vig” if you win. And finally, that 5% commission is usually only $1 on a $25 bet (instead of $1.25) to obtain true odds, or 2:1 (instead of 9:5) for your bets. This means that if you buy the four and ten and win one of them, you’ll get $50 (at 2:1) instead of $45 (at 9:5).
As previously mentioned, by placing the 6 & 8 you might lose $10 in 36 rolls. By buying the 4 & 10, you should win six times if either the four or ten hit, at 2:1 odds (6 x $50 = $300). You might also lose six times if the seven rolls, losing both of your bets (6 x $50 = $300), resulting in an exactly even proposition. If you play in a casino that only collects the vigs when you win (Binions Horseshoe in Las Vegas is one), you’ll only lose $6 in vigs for six wins, which is $4 less than you’d lose by placing the six or eight.
And now an even larger difference between the 4 & 10 and the 6 & 8 becomes evident. If you place the 6 & 8 for $30 each and lose (2 x $30 = $60), you’ll need to win twice more just to get ahead (2 x $35 = $70, at 7:6). However, if you buy the 4 & 10 for $25 each and lose (2 x $25 = $50), you’ll need to win just once more (2 x $25 = $50, at 2:1) to break even!
More and more crapshooters are trying this play, especially in casinos that only charge the vig on winning bets. So, the next time you think of placing the 6 and 8, try buying the 4 and 10 instead!
And, as always, good luck at the tables!